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Find the area of the quadrilateral whose vertices, taken in order, are (0, 0), (6, 0), (8, 5) and (1, 4).

Competition practiceGeometry

A28.5 sq units
B57 sq units
C30 sq units
D26.5 sq units

Step-by-Step Solution

Shoelace formula:

\frac{1}{2} ∣ (0 \cdot 0 - 6 \cdot 0) + (6 \cdot 5 - 8 \cdot 0) + (8 \cdot 4 - 1 \cdot 5) + (1 \cdot 0 - 0 \cdot 4) ∣ = \frac{1}{2} (30 + 27) = 28.5

sq units.

Answer: A) 28.5 sq units

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