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Find the point on the $x$ -axis that is equidistant from (2, −5) and (−2, 9).

Competition practiceGeometry

A(−7, 0)
B(7, 0)
C(0, 2)
D(−5, 0)

Step-by-Step Solution

For

(x, 0) : (x - 2)^{2} + 25 = (x + 2)^{2} + 81

. Expanding,

- 4 x + 29 = 4 x + 85

, so

x = - 7

.

Answer: A) (−7, 0)

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