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In parallelogram ABCD, ∠DAB = 75° and ∠DBC = 60°. Find ∠CDB.

Competition practiceGeometry
  • A45°
  • B60°
  • C75°
  • D105°

Step-by-Step Solution

∠ADB = ∠DBC = 60° (alternate angles, AD ∥ BC). In triangle ABD, ∠ABD = . ∠CDB = ∠ABD = 45° (alternate angles, AB ∥ DC).
Answer: A) 45°

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