- A95°
- B85°
- C75°
- D115°
Step-by-Step Solution
Draw a line through E parallel to AB. It splits ∠AEC into and (co-interior pairs). So ∠AEC = . Equivalently, ∠BAE + ∠AEC + ∠ECD = 360°.
Answer: A) 95°
In the figure, AB ∥ CD and E is a point between the two lines, to the left of A and C. If ∠BAE = 140° and ∠DCE = 125°, find ∠AEC.
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