In triangle ABC, DE ∥ BC with D on AB and E on AC. The area of triangle ADE is 25 cm² and the area of trapezium DBCE is 56 cm². Find AD : DB.

Question

Accepted Answer

5 : 4. Area of ABC = 25 + 56 = 81 cm². Triangles ADE and ABC are similar, so AD/AB = √25/81 = 5/9. Hence AD : DB = 5 : (9 − 5) = 5 : 4.

In triangle ABC, DE ∥ BC with D on AB and E on AC. The area of triangle ADE is $25 cm^{2}$ and the area of trapezium DBCE is $56 cm^{2}$ . Find AD : DB.