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PA and PB are tangents from P to a circle with centre O and radius 9 cm. If PA = 12 cm, what is the area of quadrilateral OAPB?

Competition practiceGeometry

A $108 cm^{2}$
B $54 cm^{2}$
C $135 cm^{2}$
D $216 cm^{2}$

Step-by-Step Solution

OAPB is made of two congruent right triangles OAP and OBP, each of area

\frac{1}{2} \times 9 \times 12 = 54 cm^{2}

. Total =

108 cm^{2}

.

Answer: A)

108 cm^{2}

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