- A90°
- B45°
- C135°
- D67.5°
Step-by-Step Solution
Each exterior angle of a regular octagon is 45°, so in triangle PBC, ∠PBC = ∠PCB = 45°. Hence ∠BPC = .
Answer: A) 90°
The sides AB and DC of a regular octagon ABCDEFGH are extended to meet at P. Find ∠BPC.
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