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Triangle ABC has AB = 8 cm, BC = 10 cm and CA = 12 cm. Its incircle touches AB at F. Find AF.

Competition practiceGeometry
  • A5 cm
  • B3 cm
  • C4 cm
  • D7 cm

Step-by-Step Solution

The tangent length from A is , where . So AF = 15 − 10 = 5 cm (and BF = 3 cm).
Answer: A) 5 cm

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