A piece of wire is bent to form a circle of radius 28 cm. The wire is then straightened and bent again to form a square. What is the area enclosed by the square, in square cm? (Use π = 22/7.)

The wire's length is the circle's circumference = $2\times (22/7)\times 28=176$ cm. That becomes the square's perimeter, so its side = 176/4 = 44 cm and its area = $44^2=1936$ sq cm. The trap 2464 is the area of the ORIGINAL circle, (22/7) $\times 28^2$, which the wire no longer encloses once it is reshaped; 484 follows from taking the wire's length as π$r=88$ cm, giving a side of 22 cm; $784=28^2$ uses the radius as the square's side.