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What number should follow 1, 5, 17, 53, 161 in this series?

Competition practiceNumber Series

A485
B483
C487
D322

Step-by-Step Solution

Each term is 3 times the previous plus 2:

1 \times 3 + 2 = 5, 5 \times 3 + 2 = 17, 17 \times 3 + 2 = 53, 53 \times 3 + 2 = 161, 161 \times 3 + 2 = 485

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Answer: A) 485

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