- A119
- B59
- C121
- D179
Step-by-Step Solution
Each remainder is one less than its divisor, so the number + 1 is a multiple of LCM(2, 3, 4, 5) = 60. Such numbers are 59, 119, 179, … The smallest above 100 is 119.
Answer: A) 119
A number leaves remainders 1, 2, 3 and 4 when divided by 2, 3, 4 and 5 respectively. Find the smallest such number greater than 100.
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