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Add up the cubes of the first ten natural numbers, $1^{3} + 2^{3} + \dots + 1 0^{3}$ . What is the total?

Competition practiceNumber System, HCF & LCM

A3025
B2025
C3500
D385

Step-by-Step Solution

The sum of the first

n

cubes is

(\frac{n ( n + 1 )}{2})^{2} = 5 5^{2} = 3025

. (385 is the sum of the squares.)

Answer: A) 3025

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