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Find the smallest number which leaves remainder 5 on division by each of 12, 18 and 21, and is also divisible by 11.

Competition practiceNumber System, HCF & LCM
  • A1265
  • B757
  • C509
  • D1013

Step-by-Step Solution

LCM(12, 18, 21) = 252, so the number is . Try , 2, …: 257, 509, 761, 1013, 1265, and . So and the number is 1265.
Answer: A) 1265

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