- A266
- B268
- C734
- D260
Step-by-Step Solution
Inclusion–exclusion: divisible by at least one = 500 + 333 + 200 − 166 − 100 − 66 + 33 = 734. So 1000 − 734 = 266 are divisible by none.
Answer: A) 266
How many of the numbers from 1 to 1000 are divisible by none of 2, 3 and 5?
Competition practiceNumber System, HCF & LCM
Master this topic in 30 minutes a day.
Don't just memorise the answer — build a daily practice habit.
Practice 5 Similar Questions Free →All Number System, HCF & LCM practice questions
More Number System, HCF & LCM practice
How many positive divisors does 10! have?A number leaves remainder 3 when divided by 5, remainder 4 when divided by 7 and…Four consecutive natural numbers multiply to 3024. What is their sum?For how many natural numbers n from 1 to 100 is n^2 + n + 1 divisible by 7?Find the sum of all the divisors of 2^4 × 3^3 that are multiples of 6.