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The six-digit number $58 \times 362$ is exactly divisible by 11. Find the digit $x$ .

Competition practiceNumber System, HCF & LCM

A9
B4
C2
D7

Step-by-Step Solution

Alternating sum from the right:

2 - 6 + 3 - x + 8 - 5 = 2 - x

. It must be 0 (or a multiple of 11), so

x = 2

.

Answer: C) 2

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