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The sum of the digits of a two-digit number is 12. When the digits are reversed, the new number is 36 more than the original. What is the original number?

Competition practiceNumber System, HCF & LCM
  • A84
  • B57
  • C39
  • D48

Step-by-Step Solution

Let tens = t, units = u with t + u = 12. Reversing adds 36: 9(u - t) = 36, so u - t = 4. Solving gives u = 8, t = 4, number = 48.
Answer: D) 48

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