Practice30 Create account

The sum of the squares of two consecutive positive integers is 145. What is the larger of the two integers?

Competition practiceNumber System, HCF & LCM

A8
B12
C10
D9

Step-by-Step Solution

n^{2} + (n + 1)^{2} = 145

simplifies to

n^{2} + n - 72 = 0

, giving

n = 8

. The integers are 8 and 9, so the larger is 9.

Answer: D) 9

Master this topic in 30 minutes a day.

Don't just memorise the answer — build a daily practice habit.

Practice 5 Similar Questions Free →

All Number System, HCF & LCM practice questions

More Number System, HCF & LCM practice

Three consecutive odd numbers add up to 63. What is the smallest of them?The sum of the digits of a two-digit number is 11. If 45 is added to the number, its…Three consecutive odd numbers add up to 81. What is the largest of them?Three consecutive even numbers add up to 66. Find the largest of the three.Geeta thinks of two numbers whose sum is 73 and whose difference is 17. What is the…