How many 4-letter arrangements can be made from the letters of PARALLEL?

Letters: $L\times 3,A\times 2,P$, R, E. Cases: all different (5 kinds): ${}^5{P}_4=120$. One pair + two others: pair A or $L$ (2 ways), others from 4 kinds, $2\times {}^4{C}_2\times \frac{4!}{2!}=144$. Two pairs (A, L): $\frac{4!}{2!2!}=6.LLL$ + one other (4 kinds): $4\times 4=16$. Total $120+144+6+16=286$.