How many 5-digit numbers divisible by 5 can be formed from the digits 0, 1, 2, 3, 4, 5 without repetition?

Ending in 0: the other four places from 5 digits, ${}^5{P}_4=120$. Ending in 5: first digit from {1,2,3,4} (4 ways), middle three from the remaining 4 digits, ${}^4{P}_3=24$ → 96. Total 216.