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Nine different toys are shared so that Anu gets 4, Babu gets 3 and Chiku gets 2. In how many ways can this be done?

Competition practicePermutations & Combinations

A7560
B210
C1260
D362880

Step-by-Step Solution

Anu's 4:

^{9} C_{4} = 126

. Babu's 3 from the remaining 5:

^{5} C_{3} = 10

. Chiku takes the last 2.

126 \times 10 = 1260

, i.e.

\frac{9 !}{4 ! 3 ! 2 !}

.

Answer: C) 1260

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