Tap A fills a tank in 6 hours and tap B in 4 hours. A is opened at 9 a.m., B at 10 a.m., and a drain C that alone empties the full tank in 3 hours is opened at 11 a.m. At what time will the tank be full?

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Accepted Answer

4 p.m.. 9–10: 1/6. 10–11: 1/6+1/4=5/12, total 7/12. From 11 a.m. net 1/6+1/4-1/3=1/12; 5/12 takes 5 h → 4 p.m.

Tap A fills a tank in 6 hours and tap B in 4 hours. A is opened at 9 a.m., B at 10 a.m., and a drain C that alone empties the full tank in 3 hours is opened at 11 a.m. At what time will the tank be full?

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