Water flows at 2 m/s through a pipe of internal radius 2 cm into a cylindrical tank of base radius 80 cm. By how much does the water level in the tank rise in 10 minutes?

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Accepted Answer

75 cm. Rise =\π r^2 × vt/\π R^2= (2/80 )^2×(2×600) m =1200/1600 m =0.75 m =75 cm. (30 m uses the radius ratio without squaring.)

Water flows at 2 m/s through a pipe of internal radius 2 cm into a cylindrical tank of base radius 80 cm. By how much does the water level in the tank rise in 10 minutes?

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