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A team of 11 players is to be selected from 15 players, with 2 particular players always included. In how many ways can this be done?

Competition practiceProbability & Permutation
  • A1365
  • B286
  • C715
  • D1287

Step-by-Step Solution

The 2 fixed players take 2 of the 11 places, so 9 more must be chosen from the remaining 13: C(13,9) = C(13,4) = 715. The value 1365 = C(15,11) ignores the condition.
Answer: C) 715

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