Practice30Create account

Four men and four women are to be seated round a table so that no two men are neighbours. In how many ways can they be seated?

Competition practiceProbability & Permutation
  • A576
  • B288
  • C5040
  • D144

Step-by-Step Solution

Seat the four women first: round a table that can be done in (4 − 1)! = 3! = 6 ways. Four women sitting round a table leave exactly four gaps between them, and no two men can be neighbours only if each gap takes exactly one man — the four men fill those gaps in 4! = 24 ways. Total = . Trap 576 = 4! × 4! seats the women as if they were in a row and forgets that rotating the whole table repeats a seating. Trap 5040 = 7! is the unrestricted count for eight people at a table. Trap 288 halves 576 for a reflection that does not apply at a table.
Answer: D) 144

Master this topic in 30 minutes a day.

Don't just memorise the answer — build a daily practice habit.

Practice 5 Similar Questions Free →

All Probability & Permutation practice questions

More Probability & Permutation practice

A quiz panel of 5 is to be picked from 4 teachers and 7 students of a school. In how…A Pune firm must send 4 of its 9 employees to a training programme. Two of the nine,…A question paper is set in two parts: Part A carries 7 questions and Part B carries 5. A…A residents' welfare association of 12 members must appoint a president, a secretary and…A wholesaler has 12 identical steel tumblers to send out to 3 different retail shops. In…