Practice30Create account

How many 4-digit numbers divisible by 5 can be formed from the digits 0, 1, 3, 5, 7, 9 if no digit is repeated?

Competition practiceProbability & Permutation
  • A108
  • B120
  • C60
  • D96

Step-by-Step Solution

Ending in 0: . Ending in 5: first digit from {1, 3, 7, 9} (4 ways), middle two from the 4 left: . Total 108.
Answer: A) 108

Master this topic in 30 minutes a day.

Don't just memorise the answer — build a daily practice habit.

Practice 5 Similar Questions Free →

All Probability & Permutation practice questions

More Probability & Permutation practice

Using the digits 2, 3, 5 and 7 with repetition allowed, how many 4-digit numbers greater…Seven people are to sit around a round table, and two particular people must always sit…Count the ways in which 10 different beads can be strung into a necklace.A box holds 5 green and 3 yellow marbles. Two marbles are picked together at random.…A committee of 2 is chosen at random from 4 men and 5 women. What is the probability…