- A1/169
- B2/221
- C1/13
- D1/221
Step-by-Step Solution
P(first ace) = 4/52 = 1/13. With that card kept out, P(second ace) = 3/51 = 1/17. Product . The value would apply only if the first card were replaced.
Answer: D) 1/221
Two cards are drawn one after another at random from a pack of 52 playing cards, without replacement. What is the probability that both are aces?
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