A 300 m train at 72 km/h passes a 200 m train standing at Itarsi. Later the second train starts at 36 km/h and the two meet again head-on on parallel lines. How many seconds less does the second crossing take than the first?

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Accepted Answer

81/3 s. First (other train still): 300+200/20=25 s. Second (head-on): relative 72+36=108 km/h =30 m/s → 500/30=162/3 s. Saving =25-162/3=81/3 s. (50 s would be the same-direction case.)

A 300 m train at 72 km/h passes a 200 m train standing at Itarsi. Later the second train starts at 36 km/h and the two meet again head-on on parallel lines. How many seconds less does the second crossing take than the first?

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