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At 45 km/h a train arrives 20 minutes late; at 60 km/h it arrives 10 minutes early. What is the length of the journey?

Competition practiceProblems on Trains

A60 km
B120 km
C75 km
D90 km

Step-by-Step Solution

The two times differ by 30 min:

\frac{D}{45} - \frac{D}{60} = \frac{D}{180} = \frac{1}{2}

→

D = 90

km. (60 km uses only a 20-minute gap.)

Answer: D) 90 km

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