Local trains leave Sealdah every 15 minutes and run at 45 km/h. A cyclist riding on the road towards Sealdah meets one of these trains every 12 minutes. How fast is the cyclist?

Question

Accepted Answer

11.25 km/h. Trains are 45×15/60=11.25 km apart. The cyclist closes that gap in 12 min, so closing speed =11.25/0.2=56.25 km/h. Cyclist =56.25-45=11.25 km/h. (56.25 is the closing speed.)

Local trains leave Sealdah every 15 minutes and run at 45 km/h. A cyclist riding on the road towards Sealdah meets one of these trains every 12 minutes. How fast is the cyclist?

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