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X and Y are 200 km apart. Train 1 leaves X at 6:00 a.m. at 50 km/h; train 2 leaves Y at 6:30 a.m. at 75 km/h. Each turns back at once on reaching the far end. At what time do they meet for the second time?

Competition practiceProblems on Trains
  • A11:06 a.m.
  • B10:54 a.m.
  • C11:30 a.m.
  • D10:30 a.m.

Step-by-Step Solution

First meeting 7:54 a.m. Train 2 reaches X at 9:10 and turns; train 1 reaches Y at 10:00 and turns. At 10:00 train 2 is 62.5 km from X, train 1 at Y: gap 137.5 km at 125 km/h → 1.1 h → 11:06 a.m.
Answer: A) 11:06 a.m.

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