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Find the relation after solving I. $x^{2} + 9 x + 14 = 0$
II. $y^{2} + 3 y + 2 = 0$ .

Competition practiceQuadratic Comparison

A $x$ ≤ $y$
B $x < y$
C $x$ ≥ $y$
Drelation cannot be established

Step-by-Step Solution

I:

(x + 2) (x + 7) = 0

, so

x = - 2

or −7. II:

(y + 1) (y + 2) = 0

, so

y = - 1

or −2. The largest

x

(−2) equals the smallest

y

(−2), so

x

≤

y

.

Answer: A)

x

≤

y

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