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Find the relation between $x$ and $y$ : I. $3 x^{2} - 10 x + 8 = 0$
II. $4 y^{2} - 20 y + 25 = 0$

Competition practiceQuadratic Comparison

A $x < y$
B $x$ ≥ $y$
C $x > y$
D $x$ ≤ $y$

Step-by-Step Solution

I:

(3 x - 4) (x - 2) = 0

, so

x = 4/3

or 2. II:

(2 y - 5)^{2} = 0

, so

y = 2.5

. Both values of

x

are below 2.5, so

x < y

.

Answer: A)

x < y

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