I. x² − 27x + 182 = 0 II. y² − 25y + 156 = 0. Which relation between x and y is correct?

Question

Accepted Answer

x ≥ y. I factorises as (x − 13)(x − 14) = 0, so x = 13 or 14. II gives (y − 12)(y − 13) = 0, so y = 12 or 13. x is never below y and both can be 13, so x ≥ y.

I. $x^{2} - 27 x + 182 = 0$
II. $y^{2} - 25 y + 156 = 0$ . Which relation between $x$ and $y$ is correct?

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More Quadratic Comparison practice

I. x2−27x+182=0II. y2−25y+156=0. Which relation between x and y is correct?

Step-by-Step Solution

Master this topic in 30 minutes a day.

More Quadratic Comparison practice

I. $x^{2} - 27 x + 182 = 0$
II. $y^{2} - 25 y + 156 = 0$ . Which relation between $x$ and $y$ is correct?