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I. $x^{2} - 4 x + 3 = 0$
II. $y^{2} - 6 y + 9 = 0$ . Find the relation between $x$ and $y$ .

Competition practiceQuadratic Comparison

A $x$ ≤ $y$
B $x$ ≥ $y$
C $x > y$
D $x < y$

Step-by-Step Solution

x = 1

or 3;

y = 3

(repeated). Every value of

x

is less than or equal to

y

, so

x

≤

y

.

Answer: A)

x

≤

y

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