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I. $x^{2} - 6 x + 9 = 0$
II. $y^{2} - 8 y + 15 = 0$ . Solve both and choose how $x$ relates to $y$ .

Competition practiceQuadratic Comparison

A $x$ ≥ $y$
B $x < y$
C $x > y$
D $x$ ≤ $y$

Step-by-Step Solution

x = 3

(repeated root);

y = 3

or 5.

x

can equal

y

but is never greater, so

x

≤

y

.

Answer: D)

x

≤

y

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