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I. $x^{2} - x - 6 = 0$
II. $y^{2} - 15 y + 54 = 0$ . What can be said about $x$ and $y$ ?

Competition practiceQuadratic Comparison

A $x$ ≤ $y$
B $x$ ≥ $y$
C $x > y$
D $x < y$

Step-by-Step Solution

I:

(x - 3) (x + 2) = 0

→

x = 3

, −2. II:

(y - 6) (y - 9) = 0

→

y = 6

, 9. Each

x

is smaller than each

y

, so

x < y

.

Answer: D)

x < y

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