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In the equations below, find the relation between $x$ and $y$ . I. $x^{2} + 5 x + 6 = 0$
II. $y^{2} - 3 y + 2 = 0$

Competition practiceQuadratic Comparison

A $x$ ≥ $y$
B $x < y$
C $x > y$
D $x$ ≤ $y$

Step-by-Step Solution

x = - 2

or −3 and

y = 1

or 2; every value of

x

is negative and less than every value of

y

, so

x < y

.

Answer: B)

x < y

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