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In the two equations below, solve for $x$ and $y$ and choose the correct relation. I. $x^{2} - 16 x + 63 = 0$
II. $y^{2} - 4 y + 3 = 0$

Competition practiceQuadratic Comparison

A $x > y$
B $x < y$
C $x$ ≥ $y$
D $x$ ≤ $y$

Step-by-Step Solution

x = 7

or 9 and

y = 1

or 3; every value of

x

is strictly greater than every value of

y

, so

x > y

.

Answer: A)

x > y

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