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Solve both equations and determine the relationship. I. $x^{2} - 12 x + 32 = 0$
II. $y^{2} - 28 y + 192 = 0$

Competition practiceQuadratic Comparison

A $x$ ≥ $y$
B $x$ ≤ $y$
C $x < y$
D $x > y$

Step-by-Step Solution

x = 4

or 8;

y = 12

or 16. Every root of

x

is smaller than every root of

y

, so

x < y

.

Answer: C)

x < y

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