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Solve both equations and find the relation between $x$ and $y$ . I. $2 x^{2} - 11 x + 15 = 0$
II. $y^{2} - 14 y + 48 = 0$

Competition practiceQuadratic Comparison

A $x$ ≥ $y$
B $x < y$
C $x > y$
D $x$ ≤ $y$

Step-by-Step Solution

I:

(2 x - 5) (x - 3)

→

x = 2.5

, 3. II:

(y - 6) (y - 8)

→

y = 6

, 8. Both

x

-values fall short of 6, the smaller

y

-root, which gives

x < y

.

Answer: B)

x < y

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