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Solve both equations and find the relation. I. $x^{2} - 13 x + 42 = 0$
II. $y^{2} - 7 y + 12 = 0$

Competition practiceQuadratic Comparison

A $x$ ≥ $y$
B $x < y$
C $x > y$
D $x$ ≤ $y$

Step-by-Step Solution

x = 6

or 7;

y = 3

or 4. Every

x

value is strictly greater than every

y

value, so

x > y

.

Answer: C)

x > y

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