Solve both equations and select the correct relation between $x$ and $y$ . I. $x^{2} - x - 6 = 0$
II. $y^{2} - 7 y + 12 = 0$

Question

Solve both equations and select the correct relation between x and y. I. x² − x − 6 = 0 II. y² − 7y + 12 = 0

Accepted Answer

x ≤ y. I: (x − 3)(x + 2) = 0 → x = 3, −2. II: (y − 3)(y − 4) = 0 → y = 3, 4. The largest x equals the smallest y (3), so x ≤ y.

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