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Solve both equations and state the relation. I. $x^{2} - 19 x + 90 = 0$
II. $y^{2} - 7 y + 12 = 0$

Competition practiceQuadratic Comparison

A $x > y$
B $x < y$
C $x$ ≤ $y$
D $x$ ≥ $y$

Step-by-Step Solution

I gives

x = 9

or 10; II gives

y = 3

or 4. Smallest

x

(9) is greater than largest

y

(4), so

x > y

always.

Answer: A)

x > y

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