Solve I. x² − 5x + 6 = 0 II. y² − 7y + 12 = 0, then state how x and y compare.

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x ≤ y. I: (x − 2)(x − 3) = 0, so x = 2 or 3. II: (y − 3)(y − 4) = 0, so y = 3 or 4. Every x is less than or equal to every y (3 = 3 is possible), so x ≤ y.

Solve I. $x^{2} - 5 x + 6 = 0$
II. $y^{2} - 7 y + 12 = 0$ , then state how $x$ and $y$ compare.

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More Quadratic Comparison practice

Solve I. x2−5x+6=0II. y2−7y+12=0, then state how x and y compare.

Step-by-Step Solution

Master this topic in 30 minutes a day.

More Quadratic Comparison practice

Solve I. $x^{2} - 5 x + 6 = 0$
II. $y^{2} - 7 y + 12 = 0$ , then state how $x$ and $y$ compare.