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Solve I. $x^{2} - 8 x + 12 = 0$
II. $y^{2} - 15 y + 54 = 0$ . Which relation between $x$ and $y$ is correct?

Competition practiceQuadratic Comparison

A $x < y$
B $x > y$
C $x$ ≥ $y$
D $x$ ≤ $y$

Step-by-Step Solution

I:

(x - 2) (x - 6) = 0

→

x = 2

, 6. II:

(y - 6) (y - 9) = 0

→

y = 6

, 9. Every

x

is at most every

y

(6 = 6 is possible), so

x

≤

y

.

Answer: D)

x

≤

y

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