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Solve the pair and pick the correct relation: I. $x^{2} - 3 x - 10 = 0$
II. $y^{2} - 13 y + 42 = 0$

Competition practiceQuadratic Comparison

A $x > y$
B $x$ ≥ $y$
C $x$ ≤ $y$
D $x < y$

Step-by-Step Solution

I:

(x - 5) (x + 2) = 0

, so

x = 5

or −2. II:

(y - 6) (y - 7) = 0

, so

y = 6

or 7. Every

x

is below every

y

, so

x < y

.

Answer: D)

x < y

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