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Solve the two equations and choose the correct relation. I. $x^{2} + 2 x - 15 = 0$
II. $y^{2} - 9 y + 18 = 0$

Competition practiceQuadratic Comparison

A $x < y$
B $x$ ≤ $y$
C $x$ ≥ $y$
D $x > y$

Step-by-Step Solution

I:

(x + 5) (x - 3) = 0

→

x = - 5

, 3. II:

(y - 3) (y - 6) = 0

→

y = 3

, 6. The largest

x

equals the smallest

y

(3), so

x

≤

y

.

Answer: B)

x

≤

y

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