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Solve the two equations and state how $x$ and $y$ compare. I. $x^{2} - 3 x + 2 = 0$
II. $y^{2} - 7 y + 12 = 0$

Competition practiceQuadratic Comparison

A $x > y$
B $x$ ≥ $y$
C $x < y$
D $x$ ≤ $y$

Step-by-Step Solution

I:

(x - 1) (x - 2) = 0

, so

x = 1

or 2. II:

(y - 3) (y - 4) = 0

, so

y = 3

or 4. Every

x

is smaller, so

x < y

.

Answer: C)

x < y

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