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Two quadratics are given — I. $x^{2} + 5 x + 6 = 0$
II. $y^{2} - 4 y + 3 = 0$ . Pick the correct relation.

Competition practiceQuadratic Comparison

A $x < y$
B $x$ ≤ $y$
C $x$ ≥ $y$
D $x > y$

Step-by-Step Solution

I:

(x + 2) (x + 3) = 0

→

x = - 2

, −3. II:

(y - 1) (y - 3) = 0

→

y = 1

, 3. Negative

x

is always below positive

y

, so

x < y

.

Answer: A)

x < y

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