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Which relation holds? I. $x^{2} + 6 x - 16 = 0$
II. $y^{2} - 11 y + 24 = 0$

Competition practiceQuadratic Comparison

A $x$ ≥ $y$
B $x > y$
C $x < y$
D $x$ ≤ $y$

Step-by-Step Solution

I:

(x + 8) (x - 2) = 0

→

x = 2

, −8. II:

(y - 3) (y - 8) = 0

→

y = 3

, 8. Each

x

is below each

y

, so

x < y

.

Answer: C)

x < y

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